8. Compiler Error Index

Elaboration on type errors produced by the compiler. Many error messages contain links to the sections below.

8.1. Uniqueness errors

8.1.1. “Using x, but this was consumed at y.”

A core principle of uniqueness typing (see In-place Updates) is that after a variable is “consumed”, it must not be used again. For example, this is invalid, and will result in the error above:

let y = x with [0] = 0
in x

Several operations can consume a variable: array update expressions, calling a function with unique-typed parameters, or passing it as the initial value of a unique-typed loop parameter. When a variable is consumed, its aliases are also considered consumed. Aliasing is the possibility of two variables occupying the same memory at run-time. For example, this will fail as above, because y and x are aliased:

let y = x
let z = y with [0] = 0
in x

We can always break aliasing by using a copy expression:

let y = copy x
let z = y with [0] = 0
in x

8.1.2. “Would consume x, which is not consumable”

This error message occurs for programs that try to perform a consumption (such as an in-place update) on variables that are not consumable. For example, it would occur for the following program:

let f (a: []i32) =
  let a[0] = a[0]+1
  in a

Only arrays with a a unique array type can be consumed. Such a type is written by prefixing the array type with an asterisk. The program could be fixed by writing it like this:

let f (a: *[]i32) =
  let a[0] = a[0]+1
  in a

Note that this places extra obligations on the caller of the f function, since it now consumes its argument. See In-place Updates for the full details.

You can always obtain a unique copy of an array by using copy:

let f (a: []i32) =
  let a = copy a
  let a[0] = a[0]+1
  in a

But note that in most cases (although not all), this subverts the purpose of using in-place updates in the first place.

8.1.3. “Unique-typed return value of x is aliased to y, which is not consumable”

This can be caused by a function like this:

let f (xs: []i32) : *[]i32 = xs

We are saying that f returns a unique array - meaning it has no aliases - but at the same time, it aliases the parameter xs, which is not marked as being unique (see In-place Updates). This violates one of the core guarantees provided by uniqueness types, namely that a unique return value does not alias any value that might be used in the future. Imagine if this was permitted, and we had a program that used f:

let b = f a
let b[0] = x
...

The update of b is fine, but if b was allowed to alias a (hence occupying the same memory), then we would be modifying a as well, which is a violation of referential transparency.

As with most uniqueness errors, it can be fixed by using copy xs to break the aliasing. We can also change the type of f to take a unique array as input:

let f (xs: *[]i32) : *[]i32 = xs

This makes xs “consumable”, in the sense used by the error message.

8.1.4. “A unique-typed component of the return value of x is aliased to some other component”

Caused by programs like the following:

let main (xs: *[]i32) : (*[]i32, *[]i32) = (xs, xs)

While we are allowed to “consume” xs, as it is a unique parameter, this function is trying to return two unique values that alias each other. This violates one of the core guarantees provided by uniqueness types, namely that a unique return value does not alias any value that might be used in the future (see In-place Updates) - and in this case, the two values alias each other. We can fix this by inserting copies to break the aliasing:

let main (xs: *[]i32) : (*[]i32, *[]i32) = (xs, copy xs)

8.1.5. “Consuming parameter passed non-unique argument”

Caused by programs like the following:

let update (xs: *[]i32) = xs with [0] = 0

let f (ys: []i32) = update ys

The update function consumes its xs argument to perform an in-place update, as denoted by the asterisk before the type. However, the f function tries to pass an array that it is not allowed to consume (no asterisk before the type).

One solution is to change the type of f so that it also consumes its input, which allows it to pass it on to update:

let f (ys: *[]i32) = update ys

Another solution to copy the array that we pass to update:

let f (ys: []i32) = update (copy ys)

8.1.6. “Non-consuming higher-order parameter passed consuming argument.”

This error occurs when we have a higher-order function that expects a function that does not consume its arguments, and we pass it one that does:

let apply 'a 'b (f: a -> b) (x: a) = f x

let consume (xs: *[]i32) = xs with [0] = 0

let f (arr: *[]i32) = apply consume arr

We can fix this by changing consume so that it does not have to consume its argument, by adding a copy:

let consume (xs: []i32) = copy xs with [0] = 0

Or we can create a variant of apply that accepts a consuming function:

let apply 'a 'b (f: *a -> b) (x: *a) = f x

8.1.7. “Function result aliases the free variable x”

Caused by definitions such as the following:

let x = [1,2,3]

let f () = x

To simplify the tracking of aliases, the Futhark type system requires that the result of a function may only alias the function parameters, not any free variables. Use copy to fix this:

let f () = copy x

8.1.8. “Parameter x refers to size y which will not be accessible to the caller

This happens when the size of an array parameter depends on a name that cannot be expressed in the function type:

let f (x: i64, y: i64) (A: [x]bool) = true

Intuitively, this function might have the following type:

val f : (x: i64, y: i64) -> [x]bool -> bool

But this is not currently a valid Futhark type. In a function type, each parameter can be named as a whole, but it cannot be taken apart in a pattern. In this case, we could fix it by splitting the tuple parameter into two separate parameters:

let f (x: i64) (y: i64) (A: [x]bool) = true

This gives the following type:

val f : (x: i64) -> (y: i64) -> [x]bool -> bool

Another workaround is to loosen the static safety, and use a size coercion to give A its expected size:

let f (x: i64, y: i64) (A_unsized: []bool) =
  let A = A_unsized :> [x]bool
  in true

This will produce a function with the following type:

val f [d] : (i64, i64) -> [d]bool -> bool

This does however lose the constraint that the size of the array must match one of the elements of the tuple, which means the program may fail at run-time.

The error is not always due to an explicit type annotation. It might also be due to size inference:

let f (x: i64, y: i64) (A: []bool) = zip A (iota x)

Here the type rules force A to have size x, leading to a problematic type. It can be fixed using the techniques above.

8.2. Size errors

8.2.1. “Size x unused in pattern.”

Caused by expressions like this:

let [n] (y: i32) = x

And functions like this:

let f [n] (x: i32) = x

Since n is not the size of anything, it cannot be assigned a value at runtime. Hence this program is rejected.

8.2.2. “Causality check”

Causality check errors occur when the program is written in such a way that a size is needed before it is actually computed. See Causality restriction for the full rules. Contrived example:

let f (b: bool) (xs: []i32) =
  let a = [] : [][]i32
  let b = [filter (>0) xs]
  in a[0] == b[0]

Here the inner size of the array a must be the same as the inner size of b, but the inner size of b depends on a filter operation that is executed after a is constructed.

There are various ways to fix causality errors. In the above case, we could merely change the order of statements, such that b is bound first, meaning that the size is available by the time a is bound. In many other cases, we can lift out the “size-producing” expressions into a separate let-binding preceding the problematic expressions.

8.2.3. “Unknowable size x in parameter of y”

This error occurs when you define a function that can never be applied, as it requires an input of a specific size, and that size is not known. Somewhat contrived example:

let f (x: bool) =
  let n = if x then 10 else 20
  in \(y: [n]bool) -> ...

The above constructs a function that accepts an array of size 10 or 20, based on the value of x argument. But the type of f true by itself would be ?[n].[n]bool -> bool, where the n is unknown. There is no way to construct an array of the right size, so the type checker rejects this program. (In a fully dependently typed language, the type would have been [10]bool -> bool, but Futhark does not do any type-level computation.)

In most cases, this error means you have done something you didn’t actually mean to. However, in the case that that the above really is what you intend, the workaround is to make the function fully polymorphic, and then perform a size coercion to the desired size inside the function body itself:

let f (x: bool) =
  let n = if x then 10 else 20
  in \(y_any: []bool) ->
       let y = y_any :> [n]bool
       in true

This requires a check at run-time, but it is the only way to accomplish this in Futhark.

8.2.4. “Existential size would appear in function parameter of return type”

This occurs most commonly when we use function composition with one or more functions that return an existential size. Example:

filter (>0) >-> length

The filter function has this type:

val filter [n] 't : (t -> bool) -> [n]t -> ?[m].[m]t

That is, filter returns an array whose size is not known until the function actually returns. The length function has this type:

val length [n] 't : [n]t -> i64

Whenever length occurs (as in the composition above), the type checker must instantiate the [n] with the concrete symbolic size of its input array. But in the composition, that size does not actually exist until filter has been run. For that matter, the type checker does not know what >-> does, and for all it knows it may actually apply filter many times to different arrays, yielding different sizes. This makes it impossible to uniquely instantiate the type of length, and therefore the program is rejected.

The common workaround is to use pipelining instead of composition whenever we use functions with existential return types:

xs |> filter (>0) |> length

This works because |> is left-associative, and hence the xs |> filter (>0) part will be fully evaluated to a concrete array before length is reached.

We can of course also write it as length (filter (>0) xs), with no use of either pipelining or composition.

8.3. Module errors

8.3.1. “Entry points may not be declared inside modules.”

This occurs when the program uses the entry keyword inside a module:

module m = {
  entry f x = x + 1
}

Entry points can only be declared at the top level of a file. When we wish to make a function from inside a module available as an entry point, we must define a wrapper function:

module m = {
  let f x = x + 1
}

entry f = m.f

8.4. “Module x is a parametric module

A parametric module is a module-level function:

module PM (P: {val x : i64}) = {
  let y = x + 2
}

If we directly try to access the component of PM, as PM.y, we will get an error. To use PM we must first apply it to a module of the expected type:

module M = PM { val x = 2 : i64 }

Now we can say M.y. See Module System for more.

8.5. Other errors

8.5.1. “Literal out of bounds”

This occurs for overloaded constants such as 1234 that are inferred by context to have a type that is too narrow for their value. Example:

257 : u8

It is not an error to have a non-overloaded numeric constant whose value is too large for its type. The following is perfectly cromulent:

257u8

In such cases, the behaviour is overflow (so this is equivalent to 1u8).

8.5.2. “Type is ambiguous”

There are various cases where the type checker is unable to infer the full type of something. For example:

let f r = r.x

We know that r must be a record with a field called x, but maybe the record could also have other fields as well. Instead of assuming a perhaps too narrow type, the type checker signals an error. The solution is always to add a type annotation in one or more places to disambiguate the type:

let f (r: {x:bool, y:i32}) = r.x

Usually the best spot to add such an annotation is on a function parameter, as above. But for ambiguous sum types, we often have to put it on the return type. Consider:

let f (x: bool) = #some x

The type of this function is ambiguous, because the type checker must know what other possible contructors (apart from #some) are possible. We fix it with a type annotation on the return type:

let f (x: bool) : (#some bool | #none) = #just x

See Type Abbreviations for how to avoid typing long types in several places.

8.5.3. “The x operator may not be redefined”

The && and || operators have magical short-circuiting behaviour, and therefore may not be redefined. There is no way to define your own short-circuiting operators.

8.5.4. “Unmatched cases in match expression”

Futhark requires match expressions to be exhaustive - that is, cover all possible forms of the value being pattern-matches. Example:

let f (x: i32) =
  match x case 0 -> false
          case 1 -> true

Usually this is an actual bug, and you fix it by adding the missing cases. But sometimes you know that the missing cases will never actually occur at run-time. To satisfy the type checker, you can turn the final case into a wildcard that matches anything:

let f (x: i32) =
  match x case 0 -> false
          case _ -> true

Alternatively, you can add a wildcard case that explicitly asserts that it should never happen:

let f (x: i32) =
  match x case 0 -> false
          case 1 -> true
          case _ -> assert false false

See here for details on how to use assert.

8.5.5. “Full type of x is not known at this point”

When performing a record update, the type of the field we are updating must be known. This restriction is based on a limitation in the type type checker, so the notion of “known” is a bit subtle:

let f r : {x:i32} = r with x = 0

Even though the return type annotation disambiguates the type, this program still fails to type check. This is because the return type is not consulted until after the body of the function has been checked. The solution is to put a type annotation on the parameter instead:

let f (r : {x:i32}) = r with x = 0